On a graph, plot $A \left(4,6\right)$ and $B \left(2,3\right)$. Find the image of $A$ when reflected in the line $y = 0$. Name it $A'$. Find the coordinates of $B'$, the image of $B$ when reflected in the line $AA'$. Give a geometrical name for the figure $AB'A'B$. Calculate the area of the figure $AB'A'B$.
The points $A \left(4,6\right)$ and $B \left(2,3\right)$ are plotted.
Image of $A$ reflected in the line $y = 0$ (i.e. X axis) is $A' \left(4, -6\right)$
Image of $B$ reflected in the line $AA'$ is $B' \left(6, 3\right)$
$AB'A'B$ is a kite.
Area of the figure $AB'A'B = 2 \times \text{Area} \left(\triangle AB'A'\right)$
$\text{Area} \left(AB'A'\right) = \dfrac{1}{2} \times 12 \times 2 = 12 $ sq units
$\therefore \;$ Area of figure $AB'A'B = 2 \times 12 = 24$ sq units