Find the general solution of the equation $\sin 2 \theta = \dfrac{1}{2}$
$\sin 2 \theta = \dfrac{1}{2}$
$\implies$ $\sin 2 \theta = \sin \left(\dfrac{\pi}{6}\right)$
$\implies$ $2 \theta = n \pi + \left(-1\right)^n \cdot \dfrac{\pi}{6}, \;\;\; n \in Z$
$\therefore \;$ $\theta = \dfrac{n \pi}{2} + \left(-1\right)^n \cdot \dfrac{\pi}{12} \;\;\; n \in Z$