Mensuration

PQRS is a square lawn with side $PQ=42 \ m$. Two circular flower beds are there on the sides PS and QR with center at O, the intersection of its diagonals. Find the total area of the two flower beds (shaded portion).


From the figure, $PQ=QR=RS=SP=42 \ m$

$\therefore$ Area of the square lawn $= \left(\text{side}\right)^2 = 42^2 = 1764 \ m^2$ $\cdots$ (1)

$\begin{aligned} \text{Length of diagonal of the square lawn}& =SQ=PR & = & \sqrt{PQ^2 + QR^2} \\ & & & \\ & & = & \sqrt{42^2 + 42^2} = 42 \sqrt{2} \ m \end{aligned}$

$\therefore$ Diameter of the circular flower bed $=SQ=PR=42\sqrt{2} \ m$

$\therefore$ Radius of the circular flower bed $=r=21 \sqrt{2} \ m$

$\therefore$ Area of the circular flower bed $= \pi r^2 = \dfrac{22}{7} \times \left(21\sqrt{2}\right)^2 = 2772 \ m^2$ $\cdots$ (2)

$\therefore$ Area of the circular flower bed NOT covered by the square lawn

$= 2772-1764 = 1008 \ m^2$ [from equations (1) and (2)]

$\therefore$ Area of the shaded portion $= \dfrac{1008}{2} = 504 \ m^2$